The simple examples for ADSP2181

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The simple examples for ADSP2181

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The simple examples for ADSP2181

作者：佚名文章来源：Internet 点击数：更新时间：2008-4-8

{NOTE: The two little routines perform the same function, Convolutional Encoder, and the first one has a readable  }
{structure and needs more cycles. The other one has been optimized with parallel instruction and needs less cycles.}
{If your routines can satisfy the requirement of performance, I think that the readable structure of routines      }
{is the most important thing, and you usually just need optimize the core of the algorithm.                        }
{The data define and the main program are not included, I think they are easy to be added by yourself.             }
{Any questions are welcomed.                                                                                       }
{yfk 2002.12.09                                                                                                    }

{===============================================================}
{THE 1/2 RATE CONVOLUTIONAL CODE DEFINED BY THE POLYNOMIALS:    }
{ G0 = 1 + D3+ D4                                               }
{ G1 = 1 + D + D3+ D4                                           }
{     DSP TYPE:  ADSP2181/2189                                  }
{   SUBROUTINE:  INPUTDATA[CNTR] ==> OUTPUTDATA[CNTR*2]         }
{        INPUT:  CNTR,I1=^INPUTDATA                             }
{       OUTPUT:  I2=^OUTPUTDATA+CNTR*2 ( NO USE )               }
{        TIMES:  CNTR*17+15                                     }
{       AUTHOR:  yfk                                            }
{        EMAIL:  FATCAT_YFK@SINA.COM                            }
{         DATE:  2002.12.09                                     }
{===============================================================}
CONVOLUTIONAL_CODE:
        M0=-1;  M1=1;  M2=2;   M3=-2;
        L0=0;   L1=0;  L2=0;   L3=0;

        I0=^TEMP_REG;           {TEMP REGISTER 4 WORDS, BIT STREAM}
        DM(I0,M1)=0;
        DM(I0,M1)=0;
        DM(I0,M1)=0;
        DM(I0,M1)=0;            { R0--R3=0 }

        I1=^INPUTDATA;          {SOURCE DATA, BIT STREAM}
        I2=^OUTPUTDATA;         {RESULT DATA, BIT STREAM}
        DO CC_1 UNTIL CE;       {CNTR IS INPUT}
        AX0=DM(I1,M1);
        I0=^TEMP_REG+3;
        AY0=DM(I0,M0);
        AR=AX0 XOR AY0;
        AY0=DM(I0,M3);
        AR=AR XOR AY0;
        DM(I2,M1)=AR;           {  C(2K)=U(K)^R3^R2 }
        AY0=DM(I0,M2);
        AR=AR XOR AY0;
        DM(I2,M1)=AR;           {  C(2K+1)=C(2K)^R0 }
        AY0=DM(I0,M1);
        DM(I0,M3)=AY0;          { R3=R2 }
        AY0=DM(I0,M1);
        DM(I0,M3)=AY0;          { R2=R1 }
        AY0=DM(I0,M1);
        DM(I0,M0)=AY0;          { R1=R0 }
CC_1:   DM(I0,M1)=AX0;          { R0=U(K) }
        RTS;

{===============================================================}
{THE 1/2 RATE CONVOLUTIONAL CODE DEFINED BY THE POLYNOMIALS:    }
{ G0 = 1 + D3+ D4                                               }
{ G1 = 1 + D + D3+ D4                                           }
{     DSP TYPE:  ADSP2181/2189                                  }
{   SUBROUTINE:  INPUTDATA[CNTR] ==> OUTPUTDATA[CNTR*2]         }
{        INPUT:  CNTR,I1=^INPUTDATA                             }
{       OUTPUT:  I2=^OUTPUTDATA+CNTR*2 ( NO USE )               }
{        TIMES:  CNTR*12+18                                     }
{       AUTHOR:  yfk                                            }
{        EMAIL:  FATCAT_YFK@SINA.COM                            }
{         DATE:  2002.12.09                                     }
{===============================================================}
CONVOLUTIONAL_CODE:
        M0=-1;  M1=1;  M2=2;   M3=-2;
        L0=0;   L1=0;  L2=0;   L3=0;

        I0=^TEMP_REG;                 {TEMP REGISTER 4 WORDS, BIT STREAM}
        DM(I0,M1)=0;
        DM(I0,M1)=0;
        DM(I0,M1)=0;
        DM(I0,M1)=0;                  { R0--R3=0 }

        I1=^INPUTDATA;                {SOURCE DATA, BIT STREAM}
        I2=^OUTPUTDATA;               {RESULT DATA, BIT STREAM}
        I0=^TEMP_REG+3;
        M2=3;                         {MODIFY M2}
        DO CC_1 UNTIL CE;             {CNTR IS INPUT}
        AX0=DM(I1,M1);                {AX0=U(K)}
        AY0=DM(I0,M0);                {AY0=U(K-4)}
        AR=AX0 XOR AY0,AY0=DM(I0,M1); {AR=U(k)+U(K-4),AY0=U(K-3)}
        DM(I0,M3)=AY0;                {U(K-3)-->U(K-4)}
        AR=AR+AY0,AY0=DM(I0,M1);      {AR=U(k)+U(K-4)+U(K-3),AY0=U(K-2)}
        DM(I2,M1)=AR;                 {C[2K]=AR}
        DM(I0,M3)=AY0;                {U(K-2)-->U(K-3)}
        AY0=DM(I0,M1);                {AY0=U(K-1)}
        DM(I0,M0)=AY0,AR=AR+AY0;      {U(K-1)-->U(K-2),AR=U(k)+U(K-4)+U(K-3)+U(K-1)}
        DM(I2,M1)=AR;                 {C[2K+1]=AR}
CC_1:   DM(I0,M2)=AX0;                {U(K)-->U(K-1)}
        M2=2;                         {RESTORE M2}
        RTS;

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